Physics, asked by abdullqayyum88, 1 month ago

calculte the value of magnetic flux density and magnetic flux within an air core solenoid of radius 2cm and 4000 turns per unit length carrying a current of 5A?​

Answers

Answered by sourasghotekar123
0

Answer:

The value of magnetic flux density and magnetic flux within an air core solenoid of radius 2cm and 4000 turns per unit length carrying a current of 5A is 3.14×10^{-3}T

Explanation:

From the above question,

The value of magnetic flux density and magnetic flux within an air core solenoid of radius 2cm and 4000 turns per unit length carrying a current of 5A ,

Magnetic Flux Density is amount of magnetic flux through unit area taken perpendicular to direction of magnetic flux. Flux Density (B) is related to Magnetic Field (H) by B=μH.

n=50turns,

R=0.5m,

I=5A,

Magnetic flux density(B) is defined as the force acting per unit current per unit length on a wire placed at right angles to the magnetic field. Where, l = length of wire, F = total force acting on the wire, and I = current flowing through the wire.

According to Bio-sawart Law

magnetic flux density is given by B

B = \frac{U_{0} nI}{2R}

B = \frac{4\pi  * 10^{-7} * 50 * 5 }{2 * 0.5}

  = 3.14×10^{-3}T

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