Question

calcutae mean for following frequency deviation
0-8 8-16 16-24 24-32 32-40 40-48
8 7 16 24 15 7

Answer 1

Answer:

Let’s consider the assumed mean (A) = 20 From the table it’s seen that,

A = 20 and h = 8 Mean = A + h x (ΣfiuiNΣfiuiN)

= 20 + 8 x (740740)

= 20 + 1.4

= 20.4