Question

Calcutate mass percentage composition of following: 1) C6H12O6 2) CO2 3) C6H6 4) HNO3​

Answer 1

Answer:

We know that:

Mass percentage of C6H6 

 



Explanation:

Molecular mass of glucose (C6H12O6) = 6 × 12 + 1 × 12 + 6 × 16 = 72 + 12 + 96 = 180 g.

Now, to know thepercent composition of Carbon and Oxygen . We will divide their weightwith the total weight ofCO2. % C = 12.01/44.01 = 0.2729= 27.29% (we will divide 0.2729 with 100 to take the percentage).