Calcutate, percentage composition of KNO3? [ Atomic
weight of K = 39 ,N-14 and 0-18 ]
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Answer:
% K = 38.61%
% N = 13.86%
% O = 47.53%
Explanation:
Molecular weight of KNO3 = 39+14+3×16= 101 gm
% K = (39÷101)×100= 38.61%
% N = (14÷101)×100 = 13.86%
% O = (48÷101)×100 = 47.53%
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