Chemistry, asked by jainabtabassum30, 4 days ago

Calcutate, percentage composition of KNO3? [ Atomic
weight of K = 39 ,N-14 and 0-18 ]​

Answers

Answered by narendrkumar42
1

Answer:

% K = 38.61%

% N = 13.86%

% O = 47.53%

Explanation:

Molecular weight of KNO3 = 39+14+3×16= 101 gm

% K = (39÷101)×100= 38.61%

% N = (14÷101)×100 = 13.86%

% O = (48÷101)×100 = 47.53%

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