Question

Question of IAS interview

A man has such a habit, that he spends most of the day's work.

That means spending 18 rupees a day on the 18th star, just Rs. 20 3 20 d. In that case he will spend 63 rupees in the last 5 days.

Now you know what those five dates are​

Answer 1

There is only one solution:

28 and 29 of February (a leap-year) and 1, 2, and 3 of March.

(28 + 29 + 1 + 2 + 3 = 63).

Solution

If these days would be inside one month, then the dates are (x-2), (x-1), x, (x+1) and (x+2), where x is the date of the middle of 5 days.

Then the sum must be multiple of 5, since

(x-2) + (x-1) + x + (x+1) + (x+2) = 5x.

But the integer 63 is not multiple of 5. Contradiction.

Hence, the dates are partly the end of some month and the beginning of the next month.

Then, it is easy to check the the dates 28, 29, 1, 2 and 3 satisfy the condition 28 + 29 + 1 + 2 + 3 = 63.

Next, it is easy to see that there is no other solution.