Question

Call taxi fare is Rs.100 for the first 1 /5 km and Rs. 20 for each 1/5 km thereafter. The call taxi fare for a 4 km ride is​

Answer 1

Answer:

5800

Step-by-step explanation:

a=100; after every 1/5km price is increased by rs.20. hence to cover 4km the taxi fare that can be charged can be written in the form of an A.P

100,120,140,160,...

from the above A.P a(first term)=100; d =20 we get a total of 20 terms. therefore n=20

Sn =n/2(2a+(n-1)d)

on substituting and simplifying, Sn =20/2(2(100)+(20-1)(20))

Sn= 10[200+380]=5800

Answer 2

Answer:

480

Step-by-step explanation:

for 1st 1/5 km = 100

total = 4 km = 20/5 km

20/5 - 1/5 = 19/5

for 1/5 km = 20

for 19/5 km = 19*20 = 380

total = 100+380 = 480