Question

Solve the following quadratic equation for x:
X2-2(a+2)x+(a+1)(a+3)=0​

Answer 1

Answer:

x=(a+3),(a+1)

Step-by-step explanation:

the question is done by quadratic formula full answer is in the image.

Answer 2

Thank you for asking this question. Here is your answer:

x² - 2(a+2) x + (a+1)(a+3) = 0

We know that

A = 1

B = -2(a+2)

C = (a+1) (a+3)

D = B² - 4AC

= 4(a+2)² - 4(a+1)(a+3)

= 4 [a² + 4 + 4a - a² - 4a - 3]

D = 4>0

Now we will use the quadratic formula and we will get this:

x = -B + √D/2A and x = -B - √D/2A

x = 2(a+2)+2/2 and x = 2(a+2)-2/2

x = a+3 and x = a+1

Please let us know if you have any further questions.