Chemistry, asked by varshitha6628, 7 months ago

caluculate the volume of CO2 liberated when 200 grams of calcium carbonate is heated at STP

Answers

Answered by deepthi007

1

Explanation:

CaCO3 --------- CaO +CO2

100g. 56g

200g. ?

=200×56/100

=56×2=112g is liberated

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