can a body have a charge of 0.64*10^-20C ? if answer is no then why?
Answers
Answered by
27
Heya dear
We know that
q= ne
here q = 0.64 × 10-²0 C
and we know that e= 1.6× 10-¹9 c
so plug the value and let's see no of charge it have
n = 0.64× 10^ -20/1.6×10^-19
=> n = 0.64 / 16
=> n = 0.04
so this charge is not possible till now
because we know that electric charge is quantized and thus it can exists as integral multiple of e
so it is not possible.
® additional information => quarks have charge +-1/2 or 3/4
but they follow law of quantization because this law is applicable on only free charges but quarks are embedded inside the nucleus .
We know that
q= ne
here q = 0.64 × 10-²0 C
and we know that e= 1.6× 10-¹9 c
so plug the value and let's see no of charge it have
n = 0.64× 10^ -20/1.6×10^-19
=> n = 0.64 / 16
=> n = 0.04
so this charge is not possible till now
because we know that electric charge is quantized and thus it can exists as integral multiple of e
so it is not possible.
® additional information => quarks have charge +-1/2 or 3/4
but they follow law of quantization because this law is applicable on only free charges but quarks are embedded inside the nucleus .
Answered by
10
Charge is quantised
Q = n × 1.6 × 10⁻¹⁹ C
Where n = 1,2,3,4...
n should not be a fractional number. Therefore body can’t have 0.64*10⁻²⁰C charge
Q = n × 1.6 × 10⁻¹⁹ C
Where n = 1,2,3,4...
n should not be a fractional number. Therefore body can’t have 0.64*10⁻²⁰C charge
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