Question

Can a polygon have sum of all interior angles equal to 810 ?

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

No, it is not possible for a polygon to have sum of interior angles equal to 810

Step-by-step explanation:

Sum of Interior angles of a polygon of side n = (n-2)×180

Here, sum of interior angles = 810

∴ (n-2)×180 = 810

⇒ (n-2) = $\\}\frac{810}{180}$

⇒ (n-2) = $\frac{9}{2}$

⇒ n = $\frac{9}{2}$ +2

⇒ n = $\frac{13}{2}$

Since n cannot be a fraction,

∴ n ≠ $\frac{13}{2}$

Therefore it is not possible for a polygon to have sum of interior angles equal to 810.

Hope it helps!