Question

Can a polyhedron have 8 faces, 14 edges and 6 vertices? Specify reason.

please answer with proper solution please help me please​

Answer 1

Number of faces = 8

Number of vertices = 6

Number of edges = 14

F+V-E = 2 ( Euler formula)

8+6-14 = 2

14-14 = 2

0 ≠ 2

so we can conclude that a polyhedron doesn't have 8 faces, 14 edges and 6 vertices

Answer 2

Answer:

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Step-by-step explanation:

Number of faces =8

Number of vertices =16

Number of edges =26

Using Euler’s formula

F+V−E=2

8+16−26

8+16−26

−2



=2

No, a polyhedron cannot have 8 faces, 26 edges and 16 vertices.

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