Question

can a rectangular figure of area 6300 cm^2 be drawn whose breadth is 20 cm less than the length? if so,find its perimeter.

Answer 1

Answer:

let length and breadth be x, x-20 respectively

area of rectangle = L X B

area of field = x(x-20)

x² - 20x = 6300

x²-20x-6300=0

x²-90x+70x-6300=0

x(x-90)+70(x-90)

(x+70)(x-90)

x=90 cm

length = 90 cm

breadth = x-20 ie 90-20 = 70cm

perimeter of rectangle = 2(L+B)

perimeter of field = 2(90+70)

= 2*160

=320 cm