Math, asked by MURALICHMK111, 1 year ago

Can any one answer those two problems with step by step answer

Attachments:

Anonymous: which class are you
Anonymous: are you studying in cbse board
MURALICHMK111: I am 9th class,yes
MURALICHMK111: Send me the pics photo of that answers
MURALICHMK111: I will be back in 15min mean while can you plz solve these
MURALICHMK111: Write in a paper and send me a photo

Answers

Answered by kritika92661
1

Answer:

a=0 ,b=1

Step-by-step explanation:

(7+3√5/3+√5)-(7-3√5/3-√5)

=(7+3√5)(3-√5)-(7-3√5)(3+√5)/(3+√5)

=(21-7√5+9√5-15)-(21+7√5-9√5-15)/3to the power 2,-(√5) to the power2

=(21-7√5+9√5-15-21-7√5+9√5+15)/9-5

=4√5/4

=√5

=(7+3√5/3+√5)-(7+3√5/3-√5)

=a+√5*b

=√5=a+√5*b

=0+√5*1=a+√5*b

=a=0,b=1


MURALICHMK111: Can I now the second question too
kritika92661: yes why not.....
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