Question

Can any one explain the physics chapter 9 page no. 112 question no. 5
I will mark it as brainlies​

Answer 1

Answer:

the first car travels further after the brakes are applied

Explanation:

Initial speed of the first car, u = 52 Kmh-1

= 14.44 ms-1

Its final speed, v = 0 m/s

Distance travelled by first car before it comes to rest, s = ((v+u)/2)t

= ((0+14.44)/2)5

= 36.11 m

Initial speed of the second car, u = 3 Kmh-1

= 0.833 ms-1

Its final speed, V = 0 m/s

Time taken to come to rest, t = 10s

Distance travelled by the second car before it comes to rest, s = (v+u )/2 x t

= (0+0.833)/2 x 10

= 4.167 m

∴ The first car travells further after breaks are applied .