Question

can any one give solution for 1st question?​

Answer 1

Answer:

29Ω

Step-by-step explanation:

Total resistance is

14.5+25.5+60=100Ω

Current I is

$\frac{v}{r} = \frac{200}{100} = 2 \: amps$

now voltage drop across 14.5Ω is

$v = ir = 2 \times 14.5v$

$29 \: v$