Question

Can any one give the answer of this logarithm expression Log10+2log3-log2

Answer 1

log10+2log3-log2
log10+log3²-log2
log10+log9-log2. (logA+log=logA×B)
log10×9-log2
log90-log2. (logA-logB=log/B)
log90/2
log45

Answer 2

We consider, $2 log 3 = log 3^{2}$
$= log 10 + log 3^{2} - log 2$
$= log 3^{2}.10 - log 2$
$= log 90 - log 2$
$= log \frac{90}{2}$
$= log 45$
$= 1.6532$