Question

can any one please help me in this sum
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Answer 1

Given :-

The short and long hands of a clock are 8 cm and 12 cm long respectively.

To Find :-

Find the sum of distances traveled by their tips in two days i.e 48h

Solution :-

We know that

Circumference of circle = 2πr

Circumference of short hand = 2πr

Circumference of short hand = 2 × 22/7 × 8

Circumference of short hand = 44/7 × 8

Circumference of short hand = 50.2 cm

Circumference of long hand = 2πR

Circumference of long hand = 2 × 22/7 × 12

Circumference of long hand = 44/7 × 12

Circumference of long hand = 75.4 cm

Sum of distance travelled = 50.2 + 75.4

Sum of distance travelled = 125.6

Answer 2

$\underbrace{ \mathsf {GIVEN \: \: \: DATA} \: \: }:$

Radius of Long Hand(r₁) and Short Hand(r₂) of a clock are 12cm , 8cm Respectively.

$\underbrace{ \: \mathsf{TO \: \: FIND} \: \: } :$

The sum of distance travelled by both their tip in two days. i.e., 48 hours

$\underbrace{ \: \: \underbrace{ \: \mathrm{SOLUTION} \: } \: \: } :$

$\red{ \colorbox{pink}{formula}} :$

$\orange{\colorbox{red}{Circumference of Hand = 2πr}}$

then,

Circumference of Long Hand = 2πr₁

⇒ 2 × 22/7 × 12

⇒ 22/7 × 24

⇒ 75.4cm

Circumference of Hand = 2πr₂

⇒ 2 × 22/7 × 8

⇒ 22/7 × 16

⇒ 50.2cm

$\mathrm{ then}$

Sum of Distance travelled by their tips

⇒ 75.4 + 50.2

⇒ 125.6 cm