Question

write the answer of the question given in the image​

Answer 1

Explanation:

Q2.

The ball reached the height, h = 100m

The gravitational acceleration, g = 9.8 m/s^2

Here g is retardation, so g = -9.8 m/s^2

The final velocity of the ball v =0

Now the initial velocity of throwing u = ?

We know that

$v {}^{2} - u {}^{2} = 2gh$

$= > {0}^{2} - {u}^{2} = 2 \times ( - 9.8) \times 100$

$= > - {u}^{2} = - 1960$

$= > {u}^{2} = 1960$

$= > u = \sqrt{1960}$

$so \: \: u = 14 \sqrt{10} ms {}^{ - 2}$

Q3. The initial velocities of the balls thrown vertically upward are same and masses are different.The accelerations due to gravity for both the balls are also same.So both the balls will reach the same height as it does not depend on the masses of the balls.