Question

can any one plzzzzzzz help me out with this question???

plz do it in notebook and send me the attachment.....!!!!

{specially the direction}

sorry for bad handwriting... :P

Answer 1

Velocity of bus w.r.t man = velocity vector of man + velocity vector or bus
                                       = √[v(man)² + v(bus)²] = √ (20² + 20√3² ) 

                                       = √1200+400 = 40 kmph.hope it will help you

Answer 2

Let velocity of car = a
Than a vector = ai = 20i (given)
Where i is unit vector along east word direction
And let velocity of bus is = b vect
So b vec - a vec = 20root3 j
(given, here j because it's along North which is y asis)
So b = 20root 3 j +20i
Mode of b = root ( 20*20*3 + 20*20) =root 1600 = 40 m/s
And tan theta = 20root3/20=root 3
Hence angle = 60 degree towards East to north