Question

can any one slove it​

Answer 1

I hope it will help you

The solution is 100% right....

Answer 2

Answer:

$(\sqrt{2} + \sqrt{5})$

Step-by-step explanation:

Let's consider the two terms separately.

(i) First term,

$\sqrt{5 + 2\sqrt{6} }$

Now 5 can be written as 2 + 3. And, 6 as 2 x 3.

$\sqrt{2 + 3 + 2(\sqrt{2})(\sqrt{3}) }$

= $\sqrt{(\sqrt{2})^2 + (\sqrt{3})^2 + 2(\sqrt{2})(\sqrt{3}) }$

= $\sqrt{(\sqrt{2} + \sqrt{3}) ^ 2 }$

The square and the root cancel each other and it becomes

$(\sqrt{2} + \sqrt{3})$

(i) Second term,

$\sqrt{8 - 2\sqrt{15} }$

= $\sqrt{3 + 5 - 2(\sqrt{3})(\sqrt{5}) }$

= $\sqrt{(\sqrt{3})^2 + (\sqrt{5})^2 - 2(\sqrt{3})(\sqrt{5}) }$

= $\sqrt{(\sqrt{5} - \sqrt{3}) ^ 2 }$

The square and the root cancel each other and it becomes

$(\sqrt{5} - \sqrt{3})$

Adding the two terms, we get,

$(\sqrt{2} + \sqrt{5})$