Question

Can any one solve!!!!No spamming guyz.....​

Answer 1

let the 1st 2 given boxes be x and y.

and last 2 boxes be a and b.

Now, ATQ-

x+y=8,x=8-y

a-b=6

x+a=13.....(i) , x=13-a

y+b=8,y=8-b

see equation (i)

x+a=13

8-y+a=13

8-(8-b)+a=13

8-8+b+a=13

=> a+b = 13

now, we have

a-b=6,a=6+b...(ii)

&

a+b=13..(iii)

putting (ii) in ( iii)

we get

a+b=13

=>6+b+b=13

6+2b=13

2b=7

$b = \frac{7}{2}$

$a = 6 + b = 6 + \frac{7}{2} = \frac{19}{2}$

now x= 13-a

$x = 13 - \frac{19}{2}$

$x = \frac{7}{2}$

also , y= 8-b

$y = 8 - \frac{7}{2}$

$y = \frac{9}{2}$

HOPE IT HELPS.

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Answer 2

Answer:

Listen Dear its karan511671 here

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