can any one tell the question of chapter triangles congruency in this, find the value of x in the following figure please help.
Attachments:
gnanich:
hii
ayishaa
Answers
Answered by
1
Hi friend!
Since ∆ADC is isosceles, Angle A = Angle D
I don't have angle symbol on my keyboard, so I'm using '/' for angle.
/A + /D + 56° = 180° (Angle Sum)
2*/A = 180° - 56°
2*/A = 124°
/A = 62°
/D = 62°
Now, ∆ABD is also isosceles.
/BDA + /ADC = 180° (Linear pair)
/BDA = 180° - 62°
/BDA = 118°
Since ∆ABD = isosceles, /B = /A = x
2x + /D = 180° (Angle Sum)
2x = 180° - 112° = 62°
x = 62° ÷ 2 = 31°
x = 31
Hope you found my answer useful. Keep Smiling!
Since ∆ADC is isosceles, Angle A = Angle D
I don't have angle symbol on my keyboard, so I'm using '/' for angle.
/A + /D + 56° = 180° (Angle Sum)
2*/A = 180° - 56°
2*/A = 124°
/A = 62°
/D = 62°
Now, ∆ABD is also isosceles.
/BDA + /ADC = 180° (Linear pair)
/BDA = 180° - 62°
/BDA = 118°
Since ∆ABD = isosceles, /B = /A = x
2x + /D = 180° (Angle Sum)
2x = 180° - 112° = 62°
x = 62° ÷ 2 = 31°
x = 31
Hope you found my answer useful. Keep Smiling!
Similar questions