can anybody get me the answer I will mark them as brainlest
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Explanation:
Given :-
- Density of first liquid = 2 kg/m³
- Density of second liquid = 3 kg/m³
- Volume of first liquid = 5 litre
- Volume of second liquid = 6 litre
To find :-
Mixed Density of the two liquids.
Solution :-
For first liquid,
density, D1 = 2 kg/m³
volume, V1 = 5 litre = 5 × 10^-3 m³
mass, M1 = density × volume
= 2 × 5 × 10^-3
= 10^-2 kg
For second liquid,
density, D2 = 3 kg/m³
volume, V2 = 6 litre = 6 × 10^-3 m³
mass, M2 = density × volume
= 3 × 6 × 10^-3
= 1.8 × 10^-2 kg
Mixed Density = M1 + M2 / V1 + V2
= 10^-2 + 1.8 × 10^-2 / 5 + 6
= 10^-2 × (1 + 1.8) / 11
= 2.8 × 10^-2 / 11
= 28g / 11 × 10^3 cm³
= 2.545 × 10^-3 g/cm³
or
= 2.545 kg/m³
Hope it helps!
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