Math, asked by roneet004, 11 months ago

Can anybody please answer this question

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Answered by YashPuri07
0

Answer:PLEASE MARK THE BRAINLIEST ANSWER

Capacity of Bucket = 28.312 L

Step-by-step explanation:

Volume of Frustum = π/3 × h (R² + r² + R × r)

                                = (22/21) × 28 (15²+12²+15×12)  

                                = 88(225 + 144 + 180)

                                = 88 × 549 = 28312 cm³

In Litre answer = 28.312 L

Answered by Anonymous
1

Volume frustum = πh/3 (R^2 +r^2 +Rr)


V======(22/7 ×28)/3 ×(144 +225 +180)

V ======88/3 × 549

V======16104 cubic cm


Capacity of the frustum is 16.104 liters

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