can anybody solve it?..class 11 question
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Given
Final temperature (desired temperature) (T2) =9°
Changing temperature in Kelvin =273+9
=282 k
Initial temp or room temperature(T1) =36°
=273+36=309
Cop of refrigerator = desired temperature / work done
(Check diagram in image)
Cop=T2/T1-T2
=282/309-282
=282/27
=10.444
So cop of refrigerator =10.444
This is ur ans hope it will help you in case of any doubt comment below
Final temperature (desired temperature) (T2) =9°
Changing temperature in Kelvin =273+9
=282 k
Initial temp or room temperature(T1) =36°
=273+36=309
Cop of refrigerator = desired temperature / work done
(Check diagram in image)
Cop=T2/T1-T2
=282/309-282
=282/27
=10.444
So cop of refrigerator =10.444
This is ur ans hope it will help you in case of any doubt comment below
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tnwramit1:
tnx for brainliest
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