Physics, asked by gautam96, 1 year ago

can anybody solve it?..class 11 question

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Answered by tnwramit1
1
Given

Final temperature (desired temperature) (T2) =9°
Changing temperature in Kelvin =273+9
=282 k

Initial temp or room temperature(T1) =36°

=273+36=309
Cop of refrigerator = desired temperature / work done

(Check diagram in image)



Cop=T2/T1-T2


=282/309-282

=282/27

=10.444


So cop of refrigerator =10.444


This is ur ans hope it will help you in case of any doubt comment below

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tnwramit1: tnx for brainliest
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