Question

can anybody solve this ques....???draw the graph of linear equation 2x-y+1=0.from your graph find the values of hand k if the graph passes through the points (h,4)and(1/2,k)

Answer 1

Final Answer : h = 3/2 , k = 2

Steps:

1) DRAWING Graph :

We will find at least points on equation 2x-y +1=0

When x = 0, y = 1

When y = 0 , x = -0.5

Join these points to get the graph of equation :

2x- y + 1 =0,

That is, straight line.

2) If Graph passes through the point (h, 4) , then x = h, y = 5

So,$2x - y + 1 = 0 \\ = > 2h - 4 + 1 = 0 \\ = > 2h - 3 = 0 \\ = > h = \frac{3}{2}$

3) If graph passes through (1/2,k) ,then

x = 1/2 , y = k

So,

$2x - y+ 1 = 0 \\ = > 2( \frac{1}{2} ) - k + 1 = 0 \\ = >1 - k + 1 = 0 \\ = > k = 2$

Hence,$\boxed {h = \frac{3}{2} \: and \: k = 2}$