can anybody solve this question
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We can rearrange it as..... {(16×2^n×2)-(4×2^n)}/{(16×2^n×4)-(2×2^n×2)}
Than we take 2^n common.....
{2^n(16×2)-2^n(4)}/{2^n(16×4)-2^n(2×2)}
={2^n(32-4)}/{2^n(64-4)}
Then we cancel 2^n...
(32-4)/(64-4)=28/60÷4/4=7/15
HOPE IT HELPS
Than we take 2^n common.....
{2^n(16×2)-2^n(4)}/{2^n(16×4)-2^n(2×2)}
={2^n(32-4)}/{2^n(64-4)}
Then we cancel 2^n...
(32-4)/(64-4)=28/60÷4/4=7/15
HOPE IT HELPS
Answered by
1
Hey,
Here's your answer to the question....
I hope this is correct....
Here's your answer to the question....
I hope this is correct....
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aditye:
the answer is 1/2 I wanted to know it's solution.
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