Question

Can anybody solve this question

Answer 1

ABC=60
ACB=90
BAC+150=180
BAC=30

Answer 2

Answer:

30°

Step-by-step explanation:

Given, ABCD is a cyclic Quadrilateral.

∴ ∠ADC + ∠ABC = 180°

∴ 120 + ∠ABC = 180°

⇒ ∠ABC = 60°

But ∠ACB = 90° {Angle in semicircle is a right angle triangle}.

In ΔABC,

⇒ ∠BAC + ∠ACB + ∠ABC = 180°

⇒ ∠BAC + 90 + 60 = 180°

⇒ ∠BAC + 150 = 180°

⇒ ∠BAC = 30°

Hope it helps!