Question

can anyone answer me the 3rd questions??

Answer 1

$\huge \bold \red{heya \:friend}$

Answer:

The zeroes of the given polynomial are a-b and a+b.

We know that

Sum of the zeroes=-b/a

a+b+a+a-b=-(-3)/1

3a=3

a=1-------(1)

Product of the zeroes=-d/a

(a+b)(a)(a-b)=-1/1

a(a²-b²)=-1------(2)

Now substituting (1) in (2),

1(1-b²)=-1

1-b²=-1

b²=-1-1

b²=-2

b=±√2

Therefore,

a=1

b=±√2

Answer 2

$\huge\bold\pink{hello!!}$

HERE IS UR ANSWER

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refer attachment !!