Question

Can anyone answer this question before 19 January?

Answer 1

In Δ OAB,

LM || AB

Then,  OL/LA = OM/MB  …………..(1)

[By using basic proportionality theorem]

In Δ OBC,

MN || BC

Then,  OM/MB=ON/NC   ………….(2)

[By using basic proportionality theorem]

From eq 1 & 2 ,

OL/LA=ON/NC

Thus, L & N are points on sides OA & OC of ∆OAC,

In a Δ OCA,

OL/LA=ON/NC

LN || AC
[By Converse of basic proportionality theorem]