Question

Find the 10th terms of GP if first term is - 3/4 and common ratio is - 2/3

Answer 1

Answer:

128/6561

Step-by-step explanation:

Here a = 3/4 and r = -2/3

As we know nth term of a GP = ar⁽ⁿ⁻¹⁾

By putting the value of a, r and n the formula we have:

T₁₀ = (3/4) ( -2/3 )⁽¹⁰⁻¹⁾

T₁₀ = (3/4) ( -2 /3 ) ⁹

T₁₀ = 3/4 * 512 / 19683

T₁₀ = 128/ 6561

Hope it helps....

Thanks....