can anyone can solve this problem pls
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Answered by
0
HELLO MATE
FIRST TAKING TRIANGLE BCD
BY USING PYTHAGOARAS THEROEM
BD²=BC²+CD²
BD²=25+144
BD=√169
BD=13
NOW BD=2BM
BM=7.5
FIRST TAKING TRIANGLE BCD
BY USING PYTHAGOARAS THEROEM
BD²=BC²+CD²
BD²=25+144
BD=√169
BD=13
NOW BD=2BM
BM=7.5
Answered by
0
area of ABCD=area ABD+area of BCD
=1/2×(6×13+5×12)
=69scm
=1/2×(6×13+5×12)
=69scm
tuka81:
can you explain me more
pls
yes
ok
BD =✓BC²+ CD²=✓12²+5²=13
area of ABD=1/2*6*13
area of right angle triangle BCD=1/2×BC×CD
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