Can anyone dare to solve this question?
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Heya user ,
Here is your answer !!
The height of the building is = 50 m .
Therefore , distance between the first car and the tower ,
tan 60° = 50 cm / their distance
=> their distance = 50/√3 cm .
Distance between the second car and the tower ,
tan 30° = 50 cm / their distance
=> their distance = 50√3 cm .
So ,distance between the two cars is
= 50√3 - 50/√3
= 50 ( √3 - 1/√3 )
= 50 ( 2 /√3 )
= 100 / √3
= 57.73 cm ...... [ Ans ]
Hope it helps !!
Here is your answer !!
The height of the building is = 50 m .
Therefore , distance between the first car and the tower ,
tan 60° = 50 cm / their distance
=> their distance = 50/√3 cm .
Distance between the second car and the tower ,
tan 30° = 50 cm / their distance
=> their distance = 50√3 cm .
So ,distance between the two cars is
= 50√3 - 50/√3
= 50 ( √3 - 1/√3 )
= 50 ( 2 /√3 )
= 100 / √3
= 57.73 cm ...... [ Ans ]
Hope it helps !!
lovedj780:
nice.right answer.
Answered by
3
Your answer is attached here.
Thanks.
Hope this helps you.
(First see the left side part and then the right side)
Thanks.
Hope this helps you.
(First see the left side part and then the right side)
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