Math, asked by krisha9850, 11 months ago

Can anyone do question-1 with method please

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Answered by Vinayak9004

1

Answer:

prime factors of 8712 are=(2*2)*2*(3*3)*(11*11)

We can see that 2 is left out thus 2 is the smallest number which on dividing 8712 gives a perfect square.

further,

√4356=66

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