Can anyone explain how x²÷2 is equal to 0
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Step-by-step explanation:
Given,
⇒x2−x−2=0
The give equation is in the form of, ax2+bx+c=0
So,
⇒a=1
⇒b=−1
⇒c=−2
Finding the discriminant of the equation,
⇒D=b2−4ac
Putting the values of a, b and c,
⇒D=(−1)2−4(1)(−2)
⇒D=9
⇒D>0
Since, D is positive, so, the equation has two distinct real roots.
Hence, the roots of the quadratic equation, x2−
Answered by
0
Answer:
Step-by-step explanation:
x²÷2= x²=x=0=x=0 that how we get 0
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