Question

Can anyone explain me completing the square method to solve an equ?? plzz

Answer 1

let an equation

x^2+2x+1

first divide the full equation by the coefficient of x^2

Here, coefficient of x^2 is 1 so we divide the full equation by 1 & it come

x^2/1+2x/1+1/1 = 0
x^2 + 2x + 1 = 0

x^2 + 2x = -1

square of the half of the coefficient of x add both sides
half of coefficient of x is = 2/2 = 1

x^2+ 2x+(1)^2 = -1+(1)^2
convert LHS in the form of (a+b)^2
(x+1)^2 = -1+1
(x+1) = o

x+1=0 &x+1=0
x = -1,-1
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