Math, asked by Anonymous, 1 year ago

Can anyone explain me how to solve this question by factorization

x²-4ax+4a²-b²=0

Anonymous: Plz answer it asap !!!

Answers

Answered by Namo11

0

x^2- 4ax+2a^2+2a^2-b^2=0
x^2- 2 (2a)(x)+2a^2+2a^2-b^2=0
(x-2a)^2+(2a^2+b^2)(2a^2-b^2)=0

Anonymous: Plz answer properly

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