Math, asked by Adrija2907, 5 months ago

Can anyone explain why height is subtracted only once from an open cuboid?​

Answers

Answered by Anonymous
10

Answer:

There are several methods of doing this question .

But the easiest one is given below:-

First find Total Surface Area of whole cuboid which is ,

Given,

Length (l) = 5cm

Breadth (b) = 5cm

Height (h) = 5cm

TSA of cuboid = 2(l*b+b*h+h*l)

= 2(5*5+5*5+5*5)

= 2(25+25+25)

= 2(75)

= 150 sq cm

Now , we know that box is open from top so we have to subtract Area of rectangle from TSA .

Area of rectangle = l*b

= 5*5

= 25 sq cm

Now,

The surface area of open cuboidal box

= TSA of cuboidal box - Area of rectangle

= 150 - 25

= 125 sq cm

Hence,

Answer - 125 sq cm

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It has 5 faces each of 25 sqmm. So surface area is 125.

Wait.. why not take the inner side? If that is also taken, it is then 250 sqcm.

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Surface area of an open cuboid box= total surface area - area of top of the box.

= 6.x^2. - x^2.

= 5.x^2.

= 5.(5)^2. cm^2.

= 125. cm^2. , Answer.

surface area of a cuboid = 2(lb + bh +hl)

L = B =H = 5cm

So,2(25 +25 + 25)

2x75

150cm^2

It is open so, 150 -25

125cm^2 ANS

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a cuboid cant have each edge equal

surface area =4l^2 =4*25=100

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