can anyone give me the step by step explanation for solving the sum ??
solve only ( iii ) and ( iv ) one
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11
3]
[4⁰ + 4² - 2³] × 3⁻²
As
a⁰ = 1
a⁻¹ = 1/a
[1 + 16 - 8] × 1/(3)²
[17 - 8] × 1/9
9 × 1/9
1
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4]
[(5)² - (1/4)⁻²] × (3/4)⁻²
[25 - (4)²] × (4/3)²
[25 - 16] × 16/9
9 × 16/9
16
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7
♡ Annyeong :) !!
Let's Simplify (iii) one
Simplify (iv) one
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