Math, asked by PURPLEARMYGIRL173, 5 hours ago

can anyone give me the step by step explanation for solving the sum ??


solve only ( iii ) and ( iv ) one ​

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Answers

Answered by Itzheartcracer
11

3]

{\textsf{\textbf{\underline{Solution :-}}}}

[4⁰ + 4² - 2³] × 3⁻²

As

a⁰ = 1

a⁻¹ = 1/a

[1 + 16 - 8] × 1/(3)²

[17 - 8] × 1/9

9 × 1/9

1

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4]

[(5)² - (1/4)⁻²] × (3/4)⁻²

[25 - (4)²] × (4/3)²

[25 - 16] × 16/9

9 × 16/9

16

Answered by itzMeGunjan
7

♡ Annyeong :) !!

Let's Simplify (iii) one

 \:  \:  \:  \:  \  \ \longrightarrow \rm{[4 {}^{0} +  {4}^{2}  -  {2}^{3}  ] \times (3) {}^{ - 2} } \\ \:  \: \:  \:  \:  \:  \:  \:   \:  \:  \:  \:   \rightarrow \: \rm{ [ 1 +16 - 8 ] \times (3) {}^{ - 2} } \\    \:  \:  \:  \:  \:  \:  \:  \: \rightarrow \rm{  [1 + 16 - 8] \times 9}\\   \:  \:  \:  \:  \:  \:  \:  \:  \rightarrow \rm{ \frac{(17 -  8) }{ 9 } } \\  \:  \:  \:  \:  \:  \rightarrow{ \cancel \frac{  9}{9}  } \\  \implies \underline{ \boxed{ \rm{ \huge{ \:  1 }}}}

Simplify (iv) one

\:  \:  \:  \:\longrightarrow \: [(5) {}^{2} - ( \frac{1}{4} )  {}^{ - 2} ] \times ( \frac{3}{4} ) {}^{ - 2}  \\ \:  \: \:  \:  \:  \:  \:  \:   \:  \:  \:  \: \rightarrow {  \rm{25 - (25 - 4 {}^{2}) } \times ( \frac{4}{3}) {}^{2}  }  \\ \:  \: \:  \:  \:  \:  \:  \:   \:  \:  \:  \: \rightarrow \: (25 - 16) \times  \frac{16}{9}  \\  \rightarrow \bold{ \cancel{9} \times  \frac{16}{ \cancel{9}} } \\\:     \implies \underline{ \boxed{ \huge{16}}}

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