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a = 2-√5 / 2+√5 b = 2+ √5 / 2-√5
a ^ 2 - b ^2
(2-√5/2+√5)^2 - ( 2+√5/2-√5)^2
=(2+√5(1/2-1))^2 - (2- √5(1/2-1))^2
=(2-√5/2)^2 - (2+√5/2)^2
= 2^2 + (√5/2)^2 - 2×2×√5/2 -2^2 - (√5/2)^2 -2×2× √5/2
= - 2(2×2× √5/2) = - 4√5
you can also find
a^2 - b ^2 = (a+b)(a-b)
this is your answer
a ^ 2 - b ^2
(2-√5/2+√5)^2 - ( 2+√5/2-√5)^2
=(2+√5(1/2-1))^2 - (2- √5(1/2-1))^2
=(2-√5/2)^2 - (2+√5/2)^2
= 2^2 + (√5/2)^2 - 2×2×√5/2 -2^2 - (√5/2)^2 -2×2× √5/2
= - 2(2×2× √5/2) = - 4√5
you can also find
a^2 - b ^2 = (a+b)(a-b)
this is your answer
Answered by
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