Can anyone help me on part 4 plzzz
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Question is:
one angle of a parallelogram is 130degree. find the other angles??
answer is:
in a parallelogram ABCD,
angle B = 130degree.
the other angles=?
therefore, angle C= angle B - alternate opposite angle.
= angle C = 130 degree.
then, angle A + angle B - linear pair angle.
therefore, angle A + 130degree=180degree.
= 180degree - 130 degree.
= 50 degree.
therefore, angle A = 50 degree.
angle D = angle A - alternate opposite angle.
angle D= 50 degree.
therefore, angle A=50degree.
angle B=130degree.
angle C =50degree.
angle D =130degree.
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