Math, asked by sayadsimnan008, 10 months ago

Can anyone help me to solve Q.29 plzz

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Answered by Anonymous
3

Answer:

        x = -6  and  y = -1

Step-by-step explanation:

\displaystyle PQ = \left(\begin{matrix}2&6\\3&9\end{matrix}\right)\left(\begin{matrix}3&x\\y&2\end{matrix}\right)=\left(\begin{matrix}6+6y&2x+12\\9+9y&3x+18\end{matrix}\right)

For this to be the zero matrix, we need

  6+6y = 0  ⇒  y = -1

and

  2x+12 = 0  ⇒  x = -6.

The other two entries, 9+9y and 3x+18, also need to be zero, and checking these, we see that yes, y = -1 and x = -6 makes this happen.

Hope this helps.

Answered by rajbarnwal5244
1

Answer:

x=-5

y=+2

-5+(+2)

-5+2

5-2

3 ans

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