Math, asked by 465physhzs, 2 months ago

Can anyone help me with Q2)

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Answered by mentorman2346
1

Answer:

Given, A(-2,-2) & B(2,-4). where, x1 = -2; x2 = 2 ; y1 =-2; y2 = -4.

P is a point of the line segment AB.

AP = 3AB/7.

According to ur question,

We know that,

7AP=3AB.

; 7AP = 3(AP+PB).

; 7AP = 3AP + 3 PB.

; AP(7-3) = 3PB.

; 4AP = 3PB.

; AP : PB = 3:4.

THEREFORE, M1:M2 = 3:4.

NOW,, SECTOR FORMULA,,

P(M1x2 +M2x1/M1+M2 , M1y2 + M2y1/M1+M2)

; P( 6-8/3+4 , -12-8/3+4)

; P(-2/7 , -20/7).

THIS IS YOUR ANSWER..

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