Can anyone help me with Q2)
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Given, A(-2,-2) & B(2,-4). where, x1 = -2; x2 = 2 ; y1 =-2; y2 = -4.
P is a point of the line segment AB.
AP = 3AB/7.
According to ur question,
We know that,
7AP=3AB.
; 7AP = 3(AP+PB).
; 7AP = 3AP + 3 PB.
; AP(7-3) = 3PB.
; 4AP = 3PB.
; AP : PB = 3:4.
THEREFORE, M1:M2 = 3:4.
NOW,, SECTOR FORMULA,,
P(M1x2 +M2x1/M1+M2 , M1y2 + M2y1/M1+M2)
; P( 6-8/3+4 , -12-8/3+4)
; P(-2/7 , -20/7).
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