Math, asked by Anonymous, 1 year ago

Can anyone help me with the 14th question?Also,can anyone solve it on the paper?

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Answers

Answered by rakeshmohata
1
Hope u like my process
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Formula to be used ::
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=> (a - b) ³ = a³ - b³ - 3ab(a-b)

=> (a - b) ² = a² + b² - 2ab
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If f(x) = x³ - 2x² + 7x + 5

Then ,
f(x-2)
 = {(x - 2)}^{3} - 2 {(x - 2)}^{2} + 7(x - 2) + 5 \\ \\ = ({x}^{3} - {2}^{3} - 3 \times x \times 2(x - 2)) - 2( {x}^{2} + {2}^{2} - 2 \times x \times 2) + 7x - 14 + 5 \\ \\ = {x}^{3} - 8 - 6 {x}^{2} + 12x - 2 {x}^{2} - 8 + 8x + 7x - 14 + 5 \\ \\ = {x}^{3} - 8 {x}^{2} + 27x - 25

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Hope this is ur required answer

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