Math, asked by niyatitodipcdg85, 1 year ago

can anyone help me with this 2nd question from the chapter permutations and combinations..

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niyatitodipcdg85: no .. how come only 8

niyatitodipcdg85: it is 40320

aRKe09: 8! = 8*7*6*5*4*3*2*1 = 40320

aRKe09: you forgot factorial

niyatitodipcdg85: oh ya. .. sorry i didnt see (!) sign on that 8 so sorry

aRKe09: hey no problem

aRKe09: question 2 is not complete

aRKe09: No data about young children us given, so we can't

aRKe09: if one is the youngest , 1 is fixed and then 7 members arranged in 7! ways

aRKe09: 7! = 7*6*5*4*3*2*1 = 5040

Answers

Answered by divergent07

may be this is your answer....

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Rajdeepsingh192837: hi

niyatitodipcdg85: hello

Rajdeepsingh192837: whats your real name

niyatitodipcdg85: the same

Rajdeepsingh192837: okhh

Rajdeepsingh192837: divergent yours

Answered by Rajdeepsingh192837

No of students =8

1. no of ways for sitting arrangments
= 8×7×6×5×4×3×2×1
=40320
2. no of ways of arrangment if youngest one is fixed
=7×6×5×4×3×2×1
= 5040

HOPE IT HELPED
PLEASE MARK IT AS BRAINLIEST

Rajdeepsingh192837: thax

Rajdeepsingh192837: thankx

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