Question

Can anyone help me with this problem....
First part​

Answer 1

Answer:

yeah konsi class ka question hai

Answer 2

$(i)$

$log(1 \frac{8}{27} )^{ \frac{1}{2} }$

We know that;

$\blue{ \boxed{\bf log(x)^{m} = m log(x) }}$

$\implies \frac{1}{2} log( \frac{35}{27} )$

We also know that;

$\blue{ \boxed{ \bf log(a) - log(b) = log( \frac{a}{b} ) }}$

$\implies \frac{1}{2} log(35) - \frac{1}{2} log(27)$

$\implies \frac{1}{2} ( log(7 \times 5) - log(3)^{3} )$

$\blue{ \boxed{ \bf log(a×b) = log(a)+log(b) }}$

$\implies \frac{1}{2} ( log(7) + log(5) - 3log(3) )$

$\implies \frac{1}{2} (0.84 + 0.69 - 3(0.47))$

$\implies \frac{1}{2} (1.53 - 1.41)$

$\implies \frac{1}{2} (0.12)$

$\orange{ \therefore log(1 \frac{8}{27} )^{ \frac{1}{2} } = 0.06 \: (appx.)}$

HOPE THAT HELPS!!

(You answered me saying we can't write 2b=b,but thats partially correct not completely)