Question

Can anyone help me with this question?​

Answer 1

Answer:

The value of the machine at the end of 1979 is Rs.20000. and the value of the machine at the end of 1981 is Rs.16928

Step-by-step explanation:

Let x be the value of machinery in the end of 1979

We are given that it is supposed to depreciate each year at 8%

So, Value of machinery after 1 year i.e. in 1980 = x-\frac{8}{100} \times xx−1008×x

We are given that machinery of a certain factory is valued at Rs.18400 at end of 1980.

x-\frac{8}{100} \times x=18400x−1008×x=18400

\frac{92}{100} \times x=1840010092×x=18400

x=18400 \times \frac{100}{92}x=18400×92100

x=20000x=20000

So, the value of the machine at the end of 1979 is Rs.20000.

Value of machine in 1980 = 18400

Value of machine after 1 year i.e. at th end of 1981 = 18400-\frac{8}{100} \times 18400 = 1692818400−1008×18400=16928

Hence the value of the machine at the end of 1979 is Rs.20000. and the value of the machine at the end of 1981 is Rs.16928