Question

can anyone help me with this questions....​

Answer 1

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1] Electric potential flows from higher electric potential to lower electric potential .

2] Force required to move the charges , Path to carry charges

3] Potential difference is measured using a Voltmeter which is connected in parallel

4] Potential difference between any two points is defined as the amount of work done in moving a unit positive charge from one point to other .

5] SI unit of potential difference is Volt and one volt is equal to the energy consumed by one joule per electric chatge.

6] Work done(W) = 25J

Charge (q) = 2.5 C

$\large\rm\bold{\underline{\boxed{Potential\:difference\:=\:\frac{Work\:done}{charge}}}}$

⇒ Potential difference = 25/2.5 = 10 volts

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