Question

can anyone please solve it..

Answer 1

Answer:

Option (C):

Explanation:

Let the First multiple be 6x.

Then the Second multiple is 6(x + 1).

Then the Third multiple is 6(x + 2).

Then the Fourth multiple is 6(x + 3).


Now,

Given that sum of four consecutive multiples of 6 is 492.

6x + 6(x + 1) + 6(x + 2) + 6(x + 3) = 492

6x + 6x + 6 + 6x + 12 + 6x + 18 = 492

24x + 36 = 492

24x = 492 - 36

24x = 456

x = 456/24

x = 19.


Now,

Substitute x = 19 in 6(x + 3).

= > 6(x + 3)

= > 6(19 + 3)

= > 6(22)

= > 132.


Therefore the largest multiple is 132.


Hope this helps!