Math, asked by ayshhrasheed, 11 months ago

Can anyone please solve this eqn
x^3 - 1.56x^2 + 0.32=0

Answers

Answered by Anonymous
1

X^3-1.5x^2= - 0.32

1.5X^2(x-1)= - 0.32

1.5x^2= - 0.32 (or) x-1= - 0.32

X^2= - 0.32/1.5 (or) x= - 0.32+1

X^2= - 0.2133 (or) x= 0.68

X= - 0.461 (or) x=0.68

(or) x=0


ayshhrasheed: There must be there values for x ryt?
Anonymous: look at the answer
Answered by Anonymous
7

Answer:

x= - 0.2133 (or) x= 0.68

Step-by-step explanation:

X³-1.5x²= - 0.32

1.5x²(x-1)= - 0.32

1.5x²= - 0.32 (or) x-1= - 0.32

x²= - 0.32/1.5 (or) x= - 0.32+1

x²= - 0.2133 (or) x= 0.68


ayshhrasheed: There must be 3 values for x as it is 3rd order equation
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